A Few Matrix Applications

Example 2 (Matrix inverse):

Final step (solving the system):

If $b = \begin{bmatrix}3 \\ 7\end{bmatrix}$, then:

$x = A^{-1} b = \begin{bmatrix} 3 & -1 \\ -2 & 1 \end{bmatrix} \begin{bmatrix}3 \\ 7\end{bmatrix} = \begin{bmatrix} 9 - 7 \\ -6 + 7 \end{bmatrix} = \begin{bmatrix}2 \\ 1\end{bmatrix}$