Boolean Identities

Suppose you are given two expressions, e.g., $(x + y)'$ and $x'y'$, and want to check if they are identical or not (i.e., to verify if $(x + y)' = x'y'$ is a valid identity or not.) You can do so by constructing the truth tables for each of the 2 expressions!

$x$$y$$x + y$$\boldsymbol{(x + y)'}$
$0$$0$$0$$1$
$0$$1$$1$$0$
$1$$0$$1$$0$
$1$$1$$1$$0$
$x$$y$$x'$$y'$ $\boldsymbol{x'y'}$
$0$$0$$1$$1$$1$
$0$$1$$1$$0$$0$
$1$$0$$0$$1$$0$
$1$$1$$0$$0$$0$

Because the sequences of bits that we got under the $(x + y)'$ and $x'y'$ columns are exactly the same: $[1, 0, 0, 0]$, this means that the expressions are equivalent, so $(x + y)' = x'y'$ is a valid identity!

Bonus point: What is the name of this identity?