Boolean Identities

Let's check if the expressions: $x+yz$ and $y+xz$ are equivalent or on:

$x$$y$$z$$yz$$\boldsymbol{x + yz}$
$0$$0$$0$$0$$0$
$0$$0$$1$$0$$0$
$0$$1$$0$$0$$0$
$0$$1$$1$$1$$1$
$1$$0$$0$$0$$1$
$1$$0$$1$$0$$1$
$1$$1$$0$$0$$1$
$1$$1$$1$$1$$1$
$x$$y$$z$$xz$$\boldsymbol{y + xz}$
$0$$0$$0$$0$$0$
$0$$0$$1$$0$$0$
$0$$1$$0$$0$$1$
$0$$1$$1$$0$$1$
$1$$0$$0$$0$$0$
$1$$0$$1$$1$$1$
$1$$1$$0$$0$$1$
$1$$1$$1$$1$$1$

Because the sequence of bits that we got under the $x + yz$ column is different from the one under the $y + xz$ column, these two expressions aren't equivalent. We say: $x + yz \neq y + xz$.